2/7y^2+3/7y+2/7=0

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Solution for 2/7y^2+3/7y+2/7=0 equation: 


y in (-oo:+oo)

(2/7)*y^2+(3/7)*y+2/7 = 0

2/7*y^2+3/7*y+2/7 = 0

DELTA = (3/7)^2-(2/7*2/7*4)

DELTA = -1/7

DELTA < 0

y belongs to the empty set

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